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Regular-Growth Identification
When does the observer’s critical scale actually equal the boundary dimension?
Standing. This note is deliberately separate from the frozen quotient–completion–observer triple. It does not modify Resolution STOP or §19 of the STOP manuscript. The triple asserts
q_c = 1 − 2^{−dim_B}; this note determines exactly when that assertion is available, and what holds when it is not.
The question#
The frozen triple identifies
The frozen page already qualifies that identity — “under regular covering growth”. This note makes that condition exact, and making it exact means separating two growth rates:
- the growth of the full resolution- quotient count , which is what Cauchy–Hadamard sees, and
- the growth of the live level- count — those vertices with a non-empty boundary below them — which is what covering the boundary requires.
These are not the same number in general. The purpose of this note is to separate them, prove the general inequality, and give a sharp criterion for equality.
Two counts#
Let be the discovery tree of a refining tower , and define
A vertex with no infinite extension below it is a dead end. Every dead end contributes to and nothing to the boundary. Clearly , and the boundary is the disjoint union of the level- cylinders over live vertices:
The theorem#
Equip with the visual metric , where is the depth of the last common ancestor.
Theorem. For every refining tower ,
Consequently, whenever the limit exists,
Proof#
Two facts about level- cylinders.
(i) They cover. Every boundary point passes through exactly one live level- vertex, so the family covers .
(ii) They are dyadically separated. If lie in distinct level- cylinders, their last common ancestor has depth , so and
Hence no set of diameter can meet two distinct level- cylinders. So any cover of by sets of diameter needs at least members, and (i) supplies a cover with exactly . Therefore
Moreover for every : a set of diameter still cannot straddle two level- cylinders, while level- cylinders have diameter and are no longer usable. So is constant on each dyadic band, and
with the analogous statement.
The equality criterion#
Since , the theorem immediately gives the general inequality
and, applying Cauchy–Hadamard to the full count,
Equality holds if and only if dead ends do not asymptotically dominate:
A sufficient condition. If the tower satisfies the finite-profile extension property — every compatible level- block extends to an infinite compatible profile — then every vertex is live, for all , and the identity holds. Equivalently: the two counts coincide, and hence the observer criticality and the boundary dimension coincide, whenever is defined as the set of realizable profiles of actual traversals rather than the combinatorial set of compatible blocks.
The criterion is sharp#
The spine-with-flourish tower makes the gap as large as possible. At each level the single live vertex takes children so that the level has full size , while only one child continues:
The boundary is a single point, so . Yet the full count is exponential. Measured:
| Tower | gap | ||||||
|---|---|---|---|---|---|---|---|
| regular 2-ary | 1.0000 | 1.0000 | 0.5000 | 0.5000 | 0.0000 | ||
| regular 3-ary | 1.5850 | 1.5850 | 0.6667 | 0.6667 | 0.0000 | ||
| regular 4-ary | 2.0000 | 2.0000 | 0.7500 | 0.7500 | 0.0000 | ||
| spine + flourish | 1.0000 | 0.0000 | 0.5000 | 0.0000 | 0.5000 | ||
| half-live | 1.0000 | 0.5000 | 0.5000 | 0.2929 | 0.2071 |
In the spine case the frozen identity would claim ; the true value is . The discrepancy is entirely dead ends.
Every pair with is realizable by such a tree, so the counterexample is not degenerate — it is the generic behaviour once dead ends are permitted.
What this does to the frozen triple#
Nothing in the frozen triple is withdrawn, and nothing in it was wrong. The conditional corollary was already stated there in prose (“under regular covering growth”); what changes here is that the condition becomes exact and checkable:
| Statement | Status |
|---|---|
| (R = 1/\limsup_j | X_j |
| unconditional (proved above) | |
| unconditional | |
| holds iff dead ends do not asymptotically dominate — the frozen page’s “regular covering growth” made exact — in particular under the finite-profile extension property |
So the honest reading of the frozen formula is: it is the extension-property case — already flagged there as “regular covering growth”, now stated exactly. Where the tower is realized by actual traversals — so that every compatible block is live — the formula is a theorem. Where the tower is a purely combinatorial inverse system, it is an upper bound on the geometry, and the true geometry is governed by the live count.
A sharper canonicity question#
The canonicity problem in Resolution STOP asks whether is tower-independent. This note explains why that is the delicate place to ask: is computed from the full count , while is computed from the live count . The live count is a property of the boundary object; the full count also counts vertices that the boundary never sees. So is a priori the more tower-sensitive of the two invariants, and a canonicity theorem for would not automatically give one for . The natural sharpened question is therefore two-part:
for admissible towers representing the same behavioural system — and only after those, whether the full counts agree.
Status#
Proved here. The box-dimension formula in terms of the live count (upper and lower); the general inequality ; the equality criterion; and the sharpness of that criterion by explicit realizable counterexample.
Still open. Whether (equivalently, the live growth rate) is a tower-invariant; whether the full count is; and the general sub-exponential classification.
Machinery used, not claimed. Cylinder covers and dyadic separation in ultrametric tree boundaries; Cauchy–Hadamard; the standard identification of box dimension with dyadic covering growth.
See also#
- Resolution STOP — the frozen triple (read §3 with this note in hand)
- STOP Operator Manuscript — §19
- Novelty Geometry — the discovery tree and its boundary
- Behavioral Quotients — the level- quotients